[π/2-(π/4+x)]=(π/2-π/4-x)=(π/4-x)
为什么cos^2[π/2-(π/4+x)]=cos^2(π/4-x)呢
1个回答
相关问题
-
为什么 cos(x/2-π/4)=sin(π/4+x/2)
-
求证:sin(π/4+x)/sin(π/4-x)+cos(π/4+x)/(π/4-x)=2/cos2x
-
f(x)=2cos(x+π/4)cos(x-π/4) =sin(2x-π/2) 其中cos(x-π/4) 是如何变成si
-
sin(x-π/4 + π/2 )=-cos(x+π/4)
-
高中三角函数.cos(π/4+x)=3/5.7π/12<x<7π/4.那为什么sin2x=-cos(π/2+2x)=7/
-
已知函数f(x)=cos(x+π/4)cos(x-π/4)+2tsinxcosx-sin(x+π/4)cos(x-π/4
-
cos(π/4-x)cos(π/4+x)=根号2/6(
-
化简sin(3π-x)cos(x-3/2)cos(4π-x)/tan(x-5π)cos(π/2+x)sin(x-5/2π
-
cos(x-π/4)=√2/10 ,x属于(π/2,3π/4)
-
设M=∫π2−π2[sinx1+x2cos4xdx,N=∫π/2−π2](sin3x+cos4x)dx,P=∫π2−π2