跪求初二二次根式典型例题.有解法,不胜感激

1个回答

  • (1)5√8-2√32+√50

    =5*3√2-2*4√2+5√2

    =√2(15-8+5)

    =12√2

    (2)(√45+√27)-(√4/3+√125)

    =(3√5+3√3)-(2√3/3+5√5)

    =-2√5+7√5/3

    (3)√4x*(√3x/2-√x/6)

    =2√x(√6x/2-√6x/6)

    =2√x*(√6x/3)

    =2/3*|x|*√6

    (4)(√32-3√3)(4√2+√27)

    =(4√2-3√3)(4√2+3√3)

    =(4√2)^2-(3√3)^2

    =32-27

    =5

    (5)(1+√2-√3)(1-√2+√3)

    =[1+(√2-√3)][1-(√2-√3)]

    =1-(√2-√3)^2

    =1-(2+3+2√6)

    =-4-2√6