求几道因式分解1.(ax+by)²+(bx-ay)²2.(x²-x)²-4(x&

2个回答

  • 1.(ax+by)²+(bx-ay)²

    = a²x²+2abxy+b²y²+b²x²-2abxy+a²y²

    =a²x²+b²y²+b²x²+a²y²

    =x²(a²+b²)+y²(a²+b²)

    =(x²+y²)(a²+b²)

    2.(x²-x)²-4(x²-x-1)

    =x4-2x³+x²-4x²+4x+4

    =x4-2x³-3x²+4x+4

    =x²(x²-2x-3)+4(x+1)

    =x²(x-3)(x+1)+4(x+1)

    =(x+1)(x³-3x²+4)

    3.4(x+y)²-9(x-y)²

    =(2x+2y)²-(3x-3y)²

    =(2x+2y+3x-3y)(2x+2y-3x+3y)

    =(5x-y)(5y-x)

    4.(a+b)(a-b)+4(b-1)

    =a²-b²+4b-4

    =a²-(b²-4b+4)

    =a²-(b-2)²

    =(a+b-2)(a-b+2)

    5.x²+4xy+4y²-2x-4y-3

    =(x+2y)²-2(x+2y)-3

    =(x+2y-3)(x+2y+1)

    6.(x+1)(x+2)(x+3)(x+4)+1

    =(x²+3x+2)(x²+7x+12)+1

    =x4+7x³+12x²+3x³+21x²+36x+2x²+14x+24+1

    =x4+10x³+35x²+50x+25

    =x²(x²+10x+25x)+10x²+50x+25

    =x²(x+5)²+10x(x+5)+25

    =[x(x+5)+5]²

    =(x²+5x+5)²

    7.3x²-11x+10

    =(3x-5)(x-2)