tanθ·cotθ-sin2θ==1-sin2θ=(cosθ-sinθ)^2
化简tanθ·cotθ-sin2θ=
2个回答
相关问题
-
化简sinθ(1+tanθ)+cosθ(1+cotθ)
-
化简(tanθ+cotθ)cosθ^2
-
求证:sin^2θtanθ+cos^2θcotθ+2sinθcosθ=tanθ+cotθ
-
化简sin(θ-5π)•cot(π2-θ)•cos(8π-θ)tan(3π-θ)•tan(θ-32π)•sin(-θ-4
-
化简 sin(θ-5π)•cot( π 2 -θ)•cos(8π-θ) tan(3π-θ)•tan(θ- 3 2 π)•
-
tan²θ+cot²θ-sin²θtan²θ-cos²θcot&sup
-
若θ为第二象限角,则sinθ/|sinθ|+√1-sin^2θ/|cosθ|+tanθ/|tanθ|+cotθ/|cot
-
化简：cot(θ+4π)•cos(θ+π)•sin2(θ+3π)tan(π+θ)•cos3(−π−θ)．
-
若f(θ)=sinθ/(|sinθ|)+cos(θ)/|cosθ|+tanθ/|tanθ|+cotθ/|cotθ|,求y
-
化简sin(θ-π)cos(θ-3/2π)cot(-θ-π)/tan(θ+3π)sec(-θ-2π)csc(π/2-θ)