Question

若(a^m+1b^n+2)·（a^2n-1·b）=a^5b^4,求m+n的值.

Answer 1

a^(m+1)b^(n+2)*a^(2n-1)*b=a^5b^4

a^(m+1+2n-1)b^(n+2+1)=a^5b^4

a^(m+2n)b^(n+3)=a^5b^4

n+3=4

n=1

m+2n=5

m+2=5

m=3

m+n=3+1=4

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