x^2/x^4+x^2+1=1/4,那么5x^4-15x^2+5/3x^2=
1个回答
条件倒一倒得到
x²+1/x²+1=4
即x²+1/x²=3
5x^4-15x^2+5/3x^2
=(5/3)(x²+1/x²)-5
=5/3×3-5
=0
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已知x^2/x^4+x^2+1=1/4 求5x^4-15x^2+5/3x^2
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.解线性方程组|X1+X2+X3+X4=5 |X1+2X2-X3+4X4=-2 |2X1-3X2-X3-5X4=-2 |