计算:2√8x^3y÷√18xy^3 (x>0 y>0)
1个回答
2√8x^3y÷√18xy^3
=2√[2xy*(2x)^2] ÷√[2xy*(3y)^2]
=4x*√2xy ÷ (3y*√2xy)
=4x /3y
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