sec50°+tan10°=?

2个回答

  • sec50+tan10

    =1/cos50 + sin10/cos10

    =2sin50/2sin50*cos50 + sin10/cos10

    =2sin50/sin100 + sin10/cos10

    =2sin50/cos10 + sin10/cos10

    =(2sin50+sin10)/cos10

    ={根据和差化积公式 sin50+sin10

    =2sin(50+10)/2 * cos(50-10)/2=2sin30*cos20} (sin50+cos20)/cos10

    ={再用和差化积公式 sin50+cos20=cos40+cos20

    =2cos(40+20)/2 * cos(40-20)/2

    =cos30 * cos10 *2

    =根号3 *cos10} 根号3 *cos10/cos10

    =根号3