1/a-1/b=5
(b-a)/(ab)=5
a-b=-5ab
(2a+3ab-2b)/(a-2ab-b)
=[2(a-b)+3ab]/[(a-b)-2ab]
=[2*(-5ab)+3ab]/(-5ab-2ab)
=(-10ab+3ab)/(-7ab)
=(-7ab)/(-7ab)
=1
1/a-1/b=5,则2a+3ab-2b/a-2ab-b的值为
3个回答
相关问题
-
(1/a)-(1/b)=5,则2a+3ab-2b/a-2ab-b的值为________________________
-
若a-b/b=1/2,则3a-5ab+2b/2b+3ab-5b的值为
-
1.已知1/a - 1/b=5,则2a+3ab-2b/a-2ab-b的值为?
-
a\1+b\1=2,则3a-2ab+3b\-4a+5ab-4b的值.
-
已知1/a-1/b=2,则(2a-ab-2b)/(a-3ab-b)的值为＿＿＿＿＿＿
-
已知a+b=2，ab=2，则[1/2]a3b+a2b2+[1/2]ab3的值为______．
-
若1/a-1/b=3,则分式2a+3ab-2b/a-2ab-b的值为多少
-
1/a - 1/b =5求2a+3ab-2b/a-ab-b的值
-
1.若1/a+1/b=3,则a-2ab+b/2a+ab+2b的值是
-
a^2-3ab=10,ab+b^2=-1,则a^2+3b^2的值为A3 B5 C7 D13