因为2√(2/3)=√4x(2/3)=√(8/3),√(2+2/3)=√(8/3),所以2√(2/3)=√(2+2/3)
因为3√(3/8)=√9x(3/8)=√(27/8),√(3+3/8)=√(27/8),所以3√(3/8)=√(3+3/8)
所以,结论为:a√[a/(a²-1)]=√a+[a/(a²-1)]
证明:因为等式左边a√[a/(a²-1)]=√(a²xa)/(a²-1)
=√a³/(a²-1)
等式右边√a+[a/(a²-1)]=√[a(a²-1)+a]/(a²-1)]
=√[(a³-a)+a]/(a²-1)]
=√a³/(a²-1)
所以等式左右两边相等,结论成立.