原式=（x^2)^4+(x^2)^3+(x^2)^2+(x^2)^1+1 =(x^2-1)(x^8+x^6+x^4+x^2+1)/(x^2-1) =(x^10-1)/(x^2-1) =(x^5-1)(x^5+1)/(x-1)(x+1) =(x^4+x^3+x^2+x+1)(x^4-x^3+x^2-x+1)
x的八次方＋x的六次方＋x的的四次方＋x的平方＋1（分解因式）谢谢了,大神帮忙啊
原式=（x^2)^4+(x^2)^3+(x^2)^2+(x^2)^1+1 =(x^2-1)(x^8+x^6+x^4+x^2+1)/(x^2-1) =(x^10-1)/(x^2-1) =(x^5-1)(x^5+1)/(x-1)(x+1) =(x^4+x^3+x^2+x+1)(x^4-x^3+x^2-x+1)