Question

若X的平方-4X+Y的平方+6Y+根号（Z-3）+13=0,求（XY）的Z次方的值

Answer 1

x^2-4x+y^2+6y+根号（Z-3）+13=0

(x^2-4x+4)+(y^2+6y+9)+根号（Z-3)=0

(x-2)^2+(x+3)^2+根号（Z-3)=0

(x-2)^2=0 x-2=0 x=2

(x+3)^2=0 x+3=0 x=-3

根号（Z-3)=0 z-3=0 z=3

(xy)^z

=(2*-3)^3

=-6^3

=-216