Question

紧急,马上就要的,已知函数f(x)=(x+1-a)/(a-x)(a属于R,且x不等于a),求证：f(x)+2+f(2a-

Answer 1

f(x)+2+f(2a-x)

=(x+1-a)/(a-x)+2+(2a-x+1-a)/(a-2a+x)

=(x+1-a)/(a-x)+2+(a-x+1)/(-a+x)

=(x+1-a)/(a-x)+2+(x-a-1)/(a-x)

=(2x-2a)/(a-x)+2

=-2+2

=0