原式=(a²-2ab+b²-a²-2ab-b²)/(a+b)(a-b)÷(a²-2ab+b²-a²-b²)/(a²-2ab+b²)
=-4ab/(a+b)(a-b)×(a-b)²/(-2ab)
=2(a-b)/(a+b)
=(2a-2b)(a+b)