2[sin(2x)-sin(2x+π/3)]
=2sin2x-2[1/2*sin2x+√3/2*cos2x]
=sin2x-√3cos2x
=2[1/2*sin2x-√3/2*cos2x]
=...
=2[sin(2x)-sin(2x+π/3)]=2sin(2x-π/3)怎么变的?
1个回答
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