Question

线性代数 齐次方程求解,要过程啊(x后的是下标）~

Answer 1

3 4 -5 7

2 -3 3 -2

4 11 -13 16

7 -2 1 3

=1 7 -8 9 =1 7 -8 9 =1 7 -8 9 =1 7 -8 9 =1 24 0 0

2 -3 3 -2 0 -17 19 -20 0 -17 19 -20 0 -17 -8 9 0 -17 -8 -9

4 11 -13 16 0 -17 19 -20 0 -17 19 -20 0 0 0 0 0 0 0 0

7 -2 1 3 0 -51 57 -60 0 0 0 0 0 0 0 0 0 0 0 0

即x1+24x2=0 所以,x1=-24x2 令,x3=c1 所以x1=(192/17)c1- (216/17)c2

-17x2-8x3+9x4=0 x2=-(8/17)x3+(9/17)x4 x4=c2 x2=(-8/17)c1+ (9/17)c2

x3=c1

x4=c2

即为此方程的解