Question

点A坐标为(0,3)圆A半径为1,点B在x轴上

Answer 1

设B(b,0),圆B的半径为r,方程(x - b)² + y² = r²

过M:(b - 2)² = r² ,r =± (b - 2)

AB² = (b - 0)² + (0 - 3)² = b² + 9 = (r + 1)²

(1) r = b - 2

b² + 9 = (b- 2 + 1)² = (b -1)²

b = -4

B(-4,0)

(2) r = 2 - b

b² + 9 = (2 - b + 1)² = (b -3)²

b = 0

B(0,0)