Question

2的64次方减一是多少?

Answer 1

2的64次方减一是多少?

2的64次方减一就是“2^64-1”

2^64-1=（2^32)^2-1=[(2^32)+1]*[(2^32)-1]==[(2^32)+1]*[(2^16)+1]*[(2^8)+1]]*[(2^4)+1]]*[(2^2)+1]*(2+1)(2-1)

= 1.844674407371 * 10 19