Question

利用matlab求方程时如果限定未知数范围,比如x*sin(x)-1/2=0,求解方程在-10到10上的解?

Answer 1

f=@(x)x.*sin(x)-1/2;

x=fsolve(f,[-10:1:10])

x =

Columns 1 through 6

-9.3714 -9.3714 -6.3619 -6.3619 -2.9726 -2.9726

Columns 7 through 12

-0.7408 0.7408 2.9726 2.9726 2.9726 6.3619

Columns 13 through 15

6.3619 9.3714 9.3714

剔除重复的值 有八个解

-9.3714 -6.3619 -2.9726 -0.7408 0.7408 2.9726 6.3619 9.3714