Question

6sin(-90°)+3sin(0°)-8sin(270°)+12cos(180°)怎么算 有简便方法吗?

Answer 1

6sin(-90°)+3sin(0°)-8sin(270°)+12cos(180°)

=6*(-1)+3*0-8*(-8)+12*(-1)

=-6+8-12

=-10

望采纳,多谢了!