1又2/9乘5/7减(-5/7)乘 5又1\9+(-13又1\3)除以7\5,
1个回答
1又2/9×5/7-(-5/7)×5又19+(-13又13)÷75
=11/9×5/7+5/7×46/9-40/3×5/7
=(11/9+46/9-40/3)×5/7
=(-7)×5/7
=-5
相关问题
1.(9又2/7+7又2/9)除以(5/7+5/9) 1/2乘3+1/3乘4+1/4乘5+1/5乘6 (都简算)
7又2分之1乘以8又9分之3乘以12.5乘以0.032加5.95除以18分之5减7.2加6.05乘以3又5
(-13又1/3)*1/5+(-6又2/3)*1/5+(196又1/7)除以5-(+76又1/7)除以5
13/10除以2又22/19-1又5/2乘13/11+7+5/1乘63/22
1又1/2乘5/7-(-5/7)乘2又1/2+(-1/2)乘5/7
简算:[9又1/5-(5/7+7.5-2又3/14)]除以7/8
(3/5加1/3)乘15 7/13乘以4/5加6/13除以5/4 (7/24减3/16)除以1/8 9/5减(2/5除以
[(7又1/13+2.4除6又2/5)+2又5/8]乘5 怎么算
11又7/9-(+9又1/10)-8又1/5-(-7又1/3)-|5又2/3-21又1/5|=
计算(1-3)乘(3-5)除(5-7)乘(7-9)除(9-11)乘(11-13)除…(2005-2007)