1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)...+1/(a+2004)(b+2004)
=1/(1*2)+1/(2*3)+...+1/(2005*2006)
=1-1/2006
=2005/2006
请问1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)...+1/(a+2004)(b+2004)如何计算
1个回答
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