∫1/x^2*sec^2(1/x)
1个回答
是不定积分吧,后面漏了dx
∫1/x^2*sec^2(1/x)dx
=-∫sec^2(1/x)d(1/x)
=-tan(1/x)+C
如果不懂,请Hi我,祝学习愉快!
相关问题
∫2/x∧2sec∧2 1/xdx
高数(sec^2.x-1)求导2sec^2.xtanx
求证sec x=1+x^2+(2/3)x^4+.
求lim (sec^2 x-1)/(1-cos x)
tan^2x+1=sec^2x怎么记住
∫sec^2x/(2+sec^2x)d(x)不定积分
f(x)=tan(x^2+1)sec2x 求f'(x)
(tan X + sec X – 1) / (tan X – sec X + 1) = (1 + sin X) / (c
解方程：(sec^2)x=1+tanx
1.y=sec^2x 求 y' 2.当f(e^x-1)=2x-1,求f(x)=___