Question

如图,等腰直角△ABC中,∠C=90°,AC=BC=1,D是BC上一点,E是CB延长线上一点,∠DAE=45°.

Answer 1

∵∠DAE=45°=∠ABC,∠BDA=∠ADE,∴△ADB∽△EDA,∴DB/AD=AB/AE,

(1-x)/√(1+x^2)=√2/y,

y=√[2(1+x^2)]/(1-x)