Question

请问 (ax+b)/(cx+d) 分离常数法的公式是什么?

Answer 1

分母是c(x+d/c)

原式=[a(x+d/c-d/c)+b]/c(x+d/c)

=[a(x+d/c)-ad/c+b]/[c(x+d/c)]

=a(x+d/c)/[c(x+d/c)]+(b-ad/c)/[c(x+d/c)]

=a/c+(b-ad/c)/(cx+d)