求∫(1,2)(x∧2-2x-3)/xdx - 知识问答

求∫(1,2)(x∧2-2x-3)/xdx

1个回答

∫[1,2] (x² - 2x - 3)/x dx
= ∫[1,2] (x - 2 - 3/x) dx
= (x²/2 - 2x - 3ln|x|)_[1,2]
= (2²/2 - 2(2) - 3ln2) - (1/2 - 2 - 3ln(1))
= 2 - 4 - 3ln2 - 1/2 + 2 + 0
= -1/2 - 3ln2

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