(1-0.5^n)/(1-0.5)
1个回答
(1-0.5^n)/(1-0.5)
=(1-0.5^n)/0.5
=(1-0.5^n)*2
=2-2*0.5^n
=2-2*0.5*0.5^(n-1)
=2-0.5^(n-1)
相关问题
1+1/2^0.5+1/3^0.5+...+1/n^0.5
根据算式是s=1+(1+2^0.5)+(1+2^0.5+3^0.5)+...(1+2^0.5+3^0.5+...+n^0
(m+0.5n-1)(m-o.5n+1)-(m-1)的平方+(0.5n+1)的平方
1^0.5+2^0.5+3^0.5+……+n^0.5和n/2+n/3+n/4+……+n/(n/2).谁大,其中n=500
已知2m2-5m-1=0,[1n2+5/n−2=0
a1=-4d,an=-4d+(n-1)d=0,得n=5 a1=-4.5d,an=-4.5d+(n-1)d=0,得n=5.
已知2m²-5m-1≒0,1/n²﹢5/n-2≒0.求n/m+m/n的值
(1)lim(x趋向0)[(1+x)^0.5+(1-x)^0.5-2]/x^2 (2)lim(n趋向无穷)sin[[(n
0*1+1*2+2*3+3*4+4*5+5*6+.+(n-1)*n=?
0.5+0.5=1 0.5/0.5=1 ,0.9+0.6=1.5 0.9/0.6=1.5 ,3.2+0.8=4 3.2/