若3/4π<α<-π/2,则sinα,cosα,tanα的大小关系
3个回答
3/4π<α<π sinαtanαcosα
π<α<5/4π tanαsinαcosα
5/4π<α<-π/2 tanαcosαsinα
相关问题
若-3π/4<α<-π/2,则sinα、cosα、tanα的大小关系
若tan(7π+α)=a,则sin(α-3π)+cos(π-α)/sin(-α)-cos(π+α)=?
已知tanα(α+π/4)=2,α(π,(3π/2)),则(2sinα+cosα)/(3cosα-2sinα)=
设tan(π+α)=2,则sin(α−π)+cos(π−α)sin(π+α)−cos(π+α)=( )
已知tan(π+α)=3,则2cos(π-α)-3sin(π+α)/4sin(α+π/2)+sin(2π-α)=
tanα=m,则sin(α+3π)+cos(π+α)/sin(-α)-cos(π+α)等于?
..sin^2(π+α)*cos(π+α)*cos(-α-2π)/tan(π+α)*sin^3(π/2+α)*sin(-
若tan(7π+α)=α,求sin(α+3π)+cos(π-α)/sin(-α)-cos(π+α)的值
tan(π+α)=3 则 sin(π+α)cos(π-α)=?
tan(π-α)*sin^2(α+π/2)*cos(2π-α)/cos^3(-α-π)*tan(2π-α) sin^2就