(4a-b)(a+b)/(4a^2b-2ab^2)

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计算：[(a+b)^2-4ab][(a-b)^2+4ab]-(a^2-b^2)^2
①4a^2+2ab+4a+b+1 ②a^2-4ab+4b^2-2a+4b+1因式分解
{ab-[3a^2b-(4a^2b+1/2ab)]-4a^2b}+3a^2b}=
ab=8 a-2b=4 求(a^2-4b^2)(a^b+2ab^2)
化简[(a-b)/(a+2b)]/[(a^2-b^2)/(a^2+4ab+b^2)]-(3a^2-4ab)/(a^2+a
a2+ab-b2=0,且a,b均为正数,则(a2-b2)/(b-a)(b-2a)+(2a2-ab)/(4a2-4ab+b
计算[(a^2-4b^2)/(a^2+4ab+4b^2)]÷[(a^2+ab-6b^2)/(a^2+5ab+6b^2)]
[(a+b)^2-4ab]/(a-b)+[(a-2b)^2+8ab〕/(a+2b)
ab=8,a-2b=4.求(a^2-4b^2)(a^2b+2ab^2)
求证:a^4+6*a^2*b^2+b^4>=4ab(a^2+b^2)