Question

27^3分之1+（根号3-1）的平方-（2分之一）的负一次方+根号3+1分之4,

Answer 1

27^(1/3)+(√3-1)^2-(1/2)^(-1)+4/(√3+1)

=(3^3)^(1/3)+(4-2√3)-2^1+4(√3-1)/(√3+1)(√3-1)

=3^(3*1/3)+4-2√3-2+4(√3-1)/2

=3^1+2-2√3+2(√3-1)

=3+2-2√3+2√3-2

=3