Question

若log2(x^2-3x-2)+ilog2(x^2+2x+1)>1,则实数的值(或范围)是?

Answer 1

解 log2(x^2-3x-2)+ilog2(x^2+2x+1)>1

所以虚部log2(x^2+2x+1)=0

x^2+2x+1=1

x(x+2)=0

x=0或x=-2

当x=0时 0-0-2=-21

所以 x=-2