(1)原式=[1/(m²-49)]÷[1/(m²-7m)]
={ 1/[(m+7)(m-7)] }÷{ 1/[(m(m-7)] }
={ 1/[(m+7)(m-7)] }×m(m-7)
=m/(m+7)
(2)原式=[(a²-16)/(a²+8a+16)]÷[(a-4)/(2a+8)]×[(a-4)/(a+4)]
=[...
化简 数学 aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
(1)原式=[1/(m²-49)]÷[1/(m²-7m)]
={ 1/[(m+7)(m-7)] }÷{ 1/[(m(m-7)] }
={ 1/[(m+7)(m-7)] }×m(m-7)
=m/(m+7)
(2)原式=[(a²-16)/(a²+8a+16)]÷[(a-4)/(2a+8)]×[(a-4)/(a+4)]
=[...