sinx=xπ/180-0.5π
两边同时乘以2
2sinx=xπ/90-π ,
两边同时cos,
就得到2sinx*cosx=cos(xπ/90-π),右边展开;
得 sin2x=cos(xπ/90)*cosπ+sin(xπ/90)*sinπ;
即 sin2x=cos(xπ/90);
即 sin2x=cos(π-xπ/90);
cos(π/2-2x )=cos(π-xπ/90);
即 π/2-2x =π-xπ/90;
所以x=45π/(π-180);
sinx=xπ/180-0.5π
两边同时乘以2
2sinx=xπ/90-π ,
两边同时cos,
就得到2sinx*cosx=cos(xπ/90-π),右边展开;
得 sin2x=cos(xπ/90)*cosπ+sin(xπ/90)*sinπ;
即 sin2x=cos(xπ/90);
即 sin2x=cos(π-xπ/90);
cos(π/2-2x )=cos(π-xπ/90);
即 π/2-2x =π-xπ/90;
所以x=45π/(π-180);