(1)电热水器的电阻:R=U²/P=220²/880=55(Ω)
(2)十分钟内该电热水器消耗的电能:
t=10min=600s
W=Pt=880×600=528000(J)
(3)电热水器的实际功率:P实=U实²/R=200²/55≈727.27(W)
答:略.
(1)电热水器的电阻:R=U²/P=220²/880=55(Ω)
(2)十分钟内该电热水器消耗的电能:
t=10min=600s
W=Pt=880×600=528000(J)
(3)电热水器的实际功率:P实=U实²/R=200²/55≈727.27(W)
答:略.