(5x+7y-3)(5x-7y+3)等于多少,
2个回答
原式=[5x+(7y-3)][5x-(7x-3)]
=25x^2-(7y-3)^2
=25x^2-49y^2+42y-9
相关问题
x-y/3=x+y/2 2x-5y=7等于多少
计算:[5X+7Y-3][5X+3-7Y]
(5x+7y-3)×(5x-7y+3)=()
(7x+2y)+(4+3x)-(15y-7) 5(x+y)-4(3x-2y)-3(2x-3y) 等于多少 两道合并同类项
送分的5x+y=7,3x-y=1 4x-3y=5,4x+6y=14 6x+7y=5,6x-7y=190.5x-3y=-1
2x减去3y等于5,4x减去5y等于7,求xy
已知x等于7加4倍根号3,y等于7-2倍根号3求5x的平方-16x y +5y
2x-y=5 7x-3y=-5
2x+3Y=-5 x+3y=-7 x-y=3
2x-3y-2=0 5x+3y=18 2x-3y=7 (2x-3y+5)/7+2y=9 2x-3y=3 6x+5y=35