(1)c/a=1/2,b=2√3,a^2=b^2+c^2
a=4,c=2,b=2√3
(2)L:Y=kx-2k+1
(kx-2k+1)^2/12+X^2/16=1
(4k^2+3)x^2+(8k-16k^2)x+16k^2-16k-44=0
b^-4ac=0第一象限所以k
(1)c/a=1/2,b=2√3,a^2=b^2+c^2
a=4,c=2,b=2√3
(2)L:Y=kx-2k+1
(kx-2k+1)^2/12+X^2/16=1
(4k^2+3)x^2+(8k-16k^2)x+16k^2-16k-44=0
b^-4ac=0第一象限所以k