12x^2y^3z-8x^3y^2z+4x^2y
2个回答
12x^2y^3z-8x^3y^2z+4x^2y
=4x^2y(3yz-2xyz+1)
相关问题
{x+y+z=12 x+2y-5z=25 3x-2y-4z=8
一.{x+2y+3z=14 2x-y-z=-3 3x+y+z=8 二.{3X-2Y-2Z=3 2X+2Y+3Z=12 X
(1)3x+4y=15 2y-z=2 x+2z=9 (2) x+y+z=8 2x+3y-z=6 3x-y+z=8 (3)
若x+2y+3z=8,4x+3y+2z=12,求x+y+z的值?
x:y:z=2:3:4,x+2y-z=12,求x,y,z
求证x^8+y^8+z^8>=x^3y^2z^2+x^2y^3z^2+x^2y^2z^3
3x-y+z=4,2x+3y-z=12,x+y+z=6
{3x-y+z=4,2x+3y-z=12,x+y+z=6
2x-3y+4z=2 4x+y+7z=3 8x+2y+3z=-5
2x+5y+4z=6,3x+y-7z=-4,4x+3y+12z=-2 求x+y+z