令x=2 y=3 z=4 ,求解就是
已知x/2=y/3=z/4,求下列各式 (1)(x+y+z)/x (2)(x-y+2x/(x-y-2z)
1个回答
相关问题
-
1、已知x/y=7/2,求x/x+y 2、已知x/2=y/3=z/4,求x+y+z/2x+3y-z!
-
已知x+y+z=1 x2+y2+z2=2 x3+y3+z3=3 求x4+y4+z4=?
-
已知x,y,z满足x/(y+z)+y/(z+x)+z/(x+y)=1,求代数式x2/(y+z)+y2/(x+z)+z2/
-
已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z
-
1.已知x:y:z=2:3:4 求(x+y)/z 的值和 (2x-y+z)/(x+y+z)
-
已知XY+X/X+Y+1=2 XZ+2X/X+Z+2=3 (Y+1)(Z+2)/Y+Z+3=4 求X+Y+Z的值
-
已知x+2y+3z=2 3x+y+2z=3 2x+3y+z=4求X+Y+Z的值
-
已知:x+2y+3z=2,3x+y+2z=3,2x+3y+z=4,求x+y+z的值
-
已知x/y=2,x/z=4,z=1,求代数式x+y+z/x-y-z
-
已知X=-√2,y=-3,z=1,求3x^2y-[ 2x^2y-(2xyz-x^2z)+4x^2z ].