解几道方程,3Q!1.(x^2-x)^2+4(3x^2-3x-7)=02.y^3+2y^2-5y-10=03.x^3-2

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  • 1.(x^2-x)^2+4(3x^2-3x-7)

    =(x^2-x)^2+12(x^2-x)^2-28

    =(x^2-x+14)(x^2-x-2)

    第一个括号内无解,第二个括号内为0

    x=2或x=-1

    2.y^3+2y^2-5y-10

    =y(y^2-5)+2(y^2-5)

    =(y+2)(y^2-5)

    y=-2 或y=√5或y=-√5

    3.x^3-2x^2+1

    =x(x^2-2x+1-1)+1

    =x(x-1)^2-(x-1)

    =(x-1)(x^2-x-1)

    x=1或x=(1+√5)/2或x=(1-√5)/2

    4.(x^2+3x)/(x^2-5x)=(x^2-5x)/(x^2+3x)

    =>x(x+3)^2=x(x-5)^2

    =>x[(x+3)^2-(x-5)^2]=0

    =>x(2x-6)=0

    x=0或x=3

    5.2(x^2+1/(x^2))-3(x+1/x)=1

    =>2(x^2+1/(x^2)+2-2)-3(x+1/x)=1

    =>2(x+1/x)^2-3(x+1/x)-5

    =>[2(x+1/x)-5](x+1/x+1)=0

    第二个括号内无解

    x=1/2或x=2