已知x/2=y/3=z/4,xyz≠0,求3x/2x+3y-5z的值.
2个回答
x/2=y/3=z/4=k
x=2k,y=3k,z=4k
3x/2x+3y-5z
=6k/(4k+9k-20k)
=-6/7
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