Question

B={3,x的平方+ax+a},C={x的平方+（a+1）x—3,1} a,x∈R,求使B=C成立的a,x的值

Answer 1

要B=C

只有 X^2+ax+a=1 (1)

X^2+（a+1)X-3=3 (2)

(2)-(1) X-3-A=2 ==>A=X-5

X^2+(X-5+1)X-6=0 2X^2-4X-6=0 (X-3)(X+1)=0

==>X1=3 X2=-1 ==>A1=-2 A2=-6