Question

关于复数的问题.z为复数,a为实常数.z^n＝a^n

Answer 1

(1)若a≥0或n是偶数,

则a^n=a^n·(cos0+isin0),

z^n=a^n(cos0+isin0)

z=|a|·[cos(2kπ/n)+isin(2kπ/n)],k=0,1,2,...,n-1

(2)若a