(Ⅰ)设甲、乙两人考试合格的事件分别为A、B,则
P(A)=
C 26
C 14 +
C 36
C 310 =
60+30
120 =
2
3 ,P(B)=
C 28
C 12 +
C 38
C 310 =
56+56
120 =
14
15
因为A、B相互独立,所以甲、乙两人考试均合格的概率为P(AB)=P(A)P(B)=
28
45
(Ⅱ)依题意,ξ=0,1,2,3.
P(ξ=0)=
C 34
C 310 =
1
30 , P(ξ=1)=
C 16
C 24
C 310 =
3
10
P(ξ=2)=
C 26
C 14
C 310 =
1
2 , P(ξ=3)=
C 36
C 310 =
1
6
甲答对试题数ξ的概率分布如下:
ξ 0 1 2 3
P
1
30
3
10
1
2
1
6 甲答对试题数ξ的数学期望Eξ=0×
1
30 +1×
3
10 +2×
1
2 +3×
1
6 =
9
5