Question

作出一个用二分法求2^x+3x=7的近似值的算法

Answer 1

#include "stdio.h"

#include "math.h"

double f(double x)

{

return pow(2,x)+3*x-7;

}

int main()

{

int i,j;

double low,mid,high;

low=-2;high=3;

while(low0)

high=mid;

else

low=mid;

}

printf("%lfn",(low+high)/2);

return 0;

}