设x=asint
则dx=acostdt
于是∫1/x√(a^2-x^2)dx
=∫(1/asintacost)acostdt
=∫(1/asint)dt
=(1/a)∫(sint/[1-(cost)^2])dt
=(-1/a)dcost/[1-(cost)^2]
往下我不细做了,你应该会做了吧?
∫1/x√(a^2-x^2)dx
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