{x^3-2y^3-3x^2y}-{3x^3-3y

{x^3-2y^3-3x^2y}-{3x^3-3y^3-7x^2y} { 化简}

2个回答

{x^3-2y^3-3x^2y}-{3x^3-3y^3-7x^2y} = x^3 - 2y^3 - 3x^2 y - 3x^3 + 3y^3 + 7x^2y = (x^3 - 3x^3) + (-2y^3 + 3y^3) +(-3x^2 y + 7x^2y) = -2x^3 + y^3 + 4x^2y

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