Question

数学方程1/7中括号1/5（x+2/3+4）+6中括号括回+8=9

Answer 1

1/7[1/5(x+2/3+4)+6]+8=9

1/7[1/5(x+2/3+4)+6]=1

1/5(x+2/3+4)+6=7

1/5(x+2/3+4)=1

x+2/3+4=5

x+2/3=1

x=1/3

1/5[1/4(1/2x+1)-3/4]=0

1/4(1/2x+1)-3/4=0

1/4(1/2x+1)=3/4

1/2x+1=3

1/2x=2

x=4

3/2[2/3(x/4-1)-2]-x=2

(x/4-1)-3-x=2

x/4-4-x=2

-3/4x=6

x=6*4/(-3)

x=-8