Question

若实数满足(x^2+x-2)^2+|x^2-3x+2|=0,则x的值为

Answer 1

(x^2+x-2)^2+|x^2-3x+2|=0

∴﹛x²+x-2=0 (x+2)(x-1)=0 x=-2或x=1

x²-3x+2=0 (x-1)(x-2)=0 x=1或x=2

∴x=1