-2x^4y^2-4/3x^3y^3+4/5x^2y^4
1个回答
-2x^4y^2-4/3x^3y^3+4/5x^2y^4
=-2x^2y^2/15*(15x^2+10xy-6y^2)
相关问题
(-2x^4)^4 y^3+2x^10(-2x^2 y)^3+2x^4*5(x^4)^3(3y)^3
计算:(-x/y^2)^4(-4x^2y/3w)^3(-6x^3y^4)除(-2xy)^3(5x^4y^2-x^2y^4
(1)﹛2x-y=5 (2) 4x-y=1 (3)5x+y=2 7x-3y=20 y=2x+3 x-3y=4 (4)3x
()·4x^2y^3=8x^5y^4-2x^4y^4-6^2y^3
5(3x+4y)=[(1/y)+(3/x)][4y+3x)≥(2+3)²=25∴3x+4y≥5∴(3x+4y)
x^5+x^4y-2x^3y^2-x^2y^3-xy^4+2y^5
肖元法4x+3y=7 2x-3y=5 (4)2x-y=5 3x+4y=2
(1)y=x^2-7x=6 (2)y=3x^4+4x^3 (3)y=x^3-x^2-4x+4 (4)y=2x^2-x^4
因式分解 x^4-2x^2y^2-4xy^3+4x^3y+y^2(4x^2+3/4y^2)