一辆汽车,自重8t,在每前进100m升高20m的坡路上行驶,汽车在匀速行驶中受到的摩擦力为车重的0.03倍

2个回答

  • (1)

    F牵=mgSinθ+0.03mg

    =80000*1/5+80000*0.03

    =18400N

    (2)

    W=FS

    =18400*1200

    =22080000J

    (3)

    P=W/t

    =22080000/300

    =73.6kW